(LeetCode) 278. First Bad Version

278. First Bad Version

• Explore : Interview > Top Interveiw Questions > Easy Collection
• 분류 : Sorting and Searching
• 난이도 : Easy

Problem

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which returns whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

Example 1

Input: n = 5, bad = 4
Output: 4
Explanation:
call isBadVersion(3) -> false
call isBadVersion(5) -> true
call isBadVersion(4) -> true
Then 4 is the first bad version.

Example 2

Input: n = 1, bad = 1
Output: 1

Constraints

• 1 <= bad <= n <= 2^31 - 1

Solution

Exapnder

/* The isBadVersion API is defined in the parent class VersionControl.
      def isBadVersion(version: Int): Boolean = {} */

class Solution: VersionControl() {
    override fun firstBadVersion(n: Int) : Int {
        var low = 1
        var high = n
        
        while (low <= high) {
            var mid = low + (high - low) / 2
            if (isBadVersion(mid)) {
                high = mid - 1
            } else {
                low = mid + 1
            }
        }
        return low
	}
}

Point of Thinking

• 이진 탐색으로 찾으면 Accepted.